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		<title>Latest threads in: Пределы числовых последовательностей и функций, Исследования функций</title>
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			<title>y=x-ln(x+1)</title>
			<link>http://seekland.info/mobile/forum/thread/4/y-x-ln-x-1/</link>
			<description><![CDATA[<p>Дослідити функцію і побудувати графік</p><br /><p>y=x-ln(x+1)</p>]]></description>
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			<pubDate>Thu, 26 Dec 2013 12:28:27 +0000</pubDate>
			<dc:creator>Остапчук Ника</dc:creator>
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